| 00:19.23 | sb0 | hmm does this work? http://laserhacker.com/wp-content/uploads/2013/06/SuperJoule3.jpg |
| 02:02.42 | DocScrutinizer05 | work for what? |
| 02:03.02 | DocScrutinizer05 | the circuit isn't all that clear on its intended purpose |
| 02:04.36 | DocScrutinizer05 | also looks terribly BOM-optimized, with no considerations about *anything* except BOM |
| 02:08.29 | DocScrutinizer05 | idly wonders if that "laser saber" is meant as an electromagnetic weapon to jam communication or even erase magnetic tapes |
| 02:14.45 | DocScrutinizer05 | meh, had to use some guessing to find http://laserhacker.com/?p=527 |
| 02:15.18 | DocScrutinizer05 | that looks like a ferrite toroid, not a rod |
| 02:17.58 | DocScrutinizer05 | meh! sb0, yes it might work, but definitely not nicely |
| 02:25.05 | DocScrutinizer05 | but I think they messed up orientation of primary and secondary coil of transformer |
| 02:27.15 | sb0 | oh yes sure, it's not nice. but does it oscillate at all and drive the transformer? |
| 02:27.48 | sb0 | the secondary circuit is driving the transistor between collector and base, not between the emitter and base as one would expect |
| 03:08.44 | DocScrutinizer05 | yeah, it looks pretty strange |
| 03:09.41 | DocScrutinizer05 | then OTOH B-W vs B-C doesn't _really_ make a difference for AC, only for DC |
| 03:10.07 | DocScrutinizer05 | s/B-W/B-E/ |
| 03:10.07 | qi-bot | DocScrutinizer05 meant: "then OTOH B-E vs B-C doesn't _really_ make a difference for AC, only for DC" |
| 03:11.10 | DocScrutinizer05 | with the coil between B-E you had no bias opening the transistor, and you'd need an additional resistor to create such bias to make the circuit start up |
| 03:15.09 | DocScrutinizer05 | anyway it's a really nasty circuit, that could easily latch up |
| 03:20.45 | DocScrutinizer05 | the components "Light" and "B"(attery) are not really defined and probably complex, with their complexity being relevant in that nasty circuit |
| 03:24.24 | DocScrutinizer05 | maybe the whole circuit is actually only working by operating the transistor in a possibly destructive way. |
| 03:44.51 | DocScrutinizer05 | but *maybe* those schematics are outright wrong |
| 03:47.01 | DocScrutinizer05 | I mean, you can't drain current from a NPN base, you only can dump current into it |
| 03:50.50 | DocScrutinizer05 | the "Light" component actually looks like it might be an LED energy-saver lamp, which means it is a Graetz-bridge with a buffer capacitor behind |
| 03:51.15 | DocScrutinizer05 | this would massively change the way this circuit works |
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| 10:22.56 | whitequark | sb0: oh that's just a joule thief |
| 10:23.21 | whitequark | sb0: wiki even has a full descrition |
| 10:23.23 | whitequark | https://en.wikipedia.org/wiki/Joule_thief#Description_of_operation |
| 10:26.14 | sb0 | whitequark, not exactly, the output is in series with the base |
| 10:26.42 | whitequark | ah, hm |
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| 23:49.58 | DocScrutinizer05 | yeag, it's terribly weird |
| 23:50.05 | DocScrutinizer05 | yeah, even |
| 23:51.17 | DocScrutinizer05 | it has one obvious advantage (if you can call advantages on a defunct design): switching off the load ('Lamp') will immanently switch off the circuit |
| 23:57.52 | DocScrutinizer05 | a joule-thief works via the positive feedback (like basically all oscillators do), so opening the C-E of transistor must make current flow through 'lamp', until transistor eventually switches off (for whatever reason, prolly saturation of the transformer) and then the feedback will need to apply *low* voltage to transistor to make a positive feedback... :-o where does the stored energy in transformer get dissipated then??!, *at |
| 23:57.53 | DocScrutinizer05 | least* this circuit needs a clamp diode E-B to allow transformer energy to power the 'lamp' while current flows from B through coil to 'lamp' and then to don't know where (mind you C-E closed) |
